python静态方法实例

yipeiwu_com6年前Python基础

本文实例讲述了python静态方法。分享给大家供大家参考。

具体实现方法如下:

复制代码 代码如下:
staticmethod Found at: __builtin__
staticmethod(function) -> method
    
    Convert a function to be a static method.
    
    A static method does not receive an implicit first argument.
    To declare a static method, use this idiom:
    
    class C:
    def f(arg1, arg2, ...): ...
    f = staticmethod(f)
    
    It can be called either on the class (e.g. C.f()) or on an
     instance
    (e.g. C().f()).  The instance is ignored except for its class.
    
    Static methods in Python are similar to those found in
     Java or C++.
    For a more advanced concept, see the classmethod builtin.
  
class Employee:
   """Employee class with static method isCrowded"""
 
   numberOfEmployees = 0  # number of Employees created
   maxEmployees = 10  # maximum number of comfortable employees
 
   def isCrowded():
      """Static method returns true if the employees are crowded"""
 
      return Employee.numberOfEmployees > Employee.maxEmployees
 
   # create static method
   isCrowded = staticmethod(isCrowded)
 
   def __init__(self, firstName, lastName):
      """Employee constructor, takes first name and last name"""
 
      self.first = firstName
      self.last = lastName
      Employee.numberOfEmployees += 1
 
   def __del__(self):
      """Employee destructor"""
 
      Employee.numberOfEmployees -= 1    
 
   def __str__(self):
      """String representation of Employee"""
 
      return "%s %s" % (self.first, self.last)
 
# main program
def main():
   answers = [ "No", "Yes" ]  # responses to isCrowded
   
   employeeList = []  # list of objects of class Employee
 
   # call static method using class
   print "Employees are crowded?",
   print answers[ Employee.isCrowded() ]
 
   print "\nCreating 11 objects of class Employee..."
 
   # create 11 objects of class Employee
   for i in range(11):
      employeeList.append(Employee("John", "Doe" + str(i)))
 
      # call static method using object
      print "Employees are crowded?",
      print answers[ employeeList[ i ].isCrowded() ]
 
   print "\nRemoving one employee..."
   del employeeList[ 0 ]
 
   print "Employees are crowded?", answers[ Employee.isCrowded() ]
 
if __name__ == "__main__":
   main()

希望本文所述对大家的Python程序设计有所帮助。

相关文章

在Django框架中运行Python应用全攻略

我们来假定下面的这些概念、字段和关系:     一个作者有姓,有名及email地址。     出版商有名称,地址,所...

python opencv人脸检测提取及保存方法

注意这里提取到的人脸图片的保存地址要改成自己要保存的地址 opencv人脸的检测模型的路径也要更改为自己安装的opencv的人脸检测模型的路径 import cv2 save_pat...

Pytorch中的variable, tensor与numpy相互转化的方法

Pytorch中的variable, tensor与numpy相互转化的方法

在使用pytorch作为深度学习的框架时,经常会遇到变量variable、张量tensor与矩阵numpy的类型的相互转化的问题,本章结合这实际图像对此转化方法进行实现。 1.加载需要用...

Python入门教程2. 字符串基本操作【运算、格式化输出、常用函数】 原创

前面简单介绍了Python基本运算,这里再来简单讲述一下Python字符串相关操作 1. 字符串表示方法 >>> "www.jb51.net" #字符串使用单引号(...

解决Django一个表单对应多个按钮的问题

需求: 在django中,有时候我们需要在一个表单中设置多个按钮实现不同的功能。 解决方法: 为不同按钮添加不同name属性,然后再后台判断name值。python2环境下,例如: 我们...