python静态方法实例

yipeiwu_com6年前Python基础

本文实例讲述了python静态方法。分享给大家供大家参考。

具体实现方法如下:

复制代码 代码如下:
staticmethod Found at: __builtin__
staticmethod(function) -> method
    
    Convert a function to be a static method.
    
    A static method does not receive an implicit first argument.
    To declare a static method, use this idiom:
    
    class C:
    def f(arg1, arg2, ...): ...
    f = staticmethod(f)
    
    It can be called either on the class (e.g. C.f()) or on an
     instance
    (e.g. C().f()).  The instance is ignored except for its class.
    
    Static methods in Python are similar to those found in
     Java or C++.
    For a more advanced concept, see the classmethod builtin.
  
class Employee:
   """Employee class with static method isCrowded"""
 
   numberOfEmployees = 0  # number of Employees created
   maxEmployees = 10  # maximum number of comfortable employees
 
   def isCrowded():
      """Static method returns true if the employees are crowded"""
 
      return Employee.numberOfEmployees > Employee.maxEmployees
 
   # create static method
   isCrowded = staticmethod(isCrowded)
 
   def __init__(self, firstName, lastName):
      """Employee constructor, takes first name and last name"""
 
      self.first = firstName
      self.last = lastName
      Employee.numberOfEmployees += 1
 
   def __del__(self):
      """Employee destructor"""
 
      Employee.numberOfEmployees -= 1    
 
   def __str__(self):
      """String representation of Employee"""
 
      return "%s %s" % (self.first, self.last)
 
# main program
def main():
   answers = [ "No", "Yes" ]  # responses to isCrowded
   
   employeeList = []  # list of objects of class Employee
 
   # call static method using class
   print "Employees are crowded?",
   print answers[ Employee.isCrowded() ]
 
   print "\nCreating 11 objects of class Employee..."
 
   # create 11 objects of class Employee
   for i in range(11):
      employeeList.append(Employee("John", "Doe" + str(i)))
 
      # call static method using object
      print "Employees are crowded?",
      print answers[ employeeList[ i ].isCrowded() ]
 
   print "\nRemoving one employee..."
   del employeeList[ 0 ]
 
   print "Employees are crowded?", answers[ Employee.isCrowded() ]
 
if __name__ == "__main__":
   main()

希望本文所述对大家的Python程序设计有所帮助。

相关文章

Python标准库之多进程(multiprocessing包)介绍

Python标准库之多进程(multiprocessing包)介绍

在初步了解Python多进程之后,我们可以继续探索multiprocessing包中更加高级的工具。这些工具可以让我们更加便利地实现多进程。 进程池 进程池 (Process Pool)...

Python实现TCP协议下的端口映射功能的脚本程序示例

Python实现TCP协议下的端口映射功能的脚本程序示例

1 端口映射 举个例子来说明一下端口映射的作用。 有A、B、C三台计算机,A、B互通,B、C互通,但是A、C不通,这个时候在C上开了一个Web服务,如何让A访问C的Web服务? 最简单有...

Django框架下在视图中使用模版的方法

 打开current_datetime 视图。 以下是其内容: from django.http import HttpResponse import datetime...

Python全栈之列表数据类型详解

前言 列表(list)同字符串一样都是有序的,因为他们都可以通过切片和索引进行数据访问,且列表是可变的。 创建列表的几种方法 第一种 name_list = ['Python',...

python检测某个变量是否有定义的方法

本文实例讲述了python检测某个变量是否有定义的方法。分享给大家供大家参考。具体如下: 第一种方法使用内置函数locals(): 'testvar'   in&nb...