Python使用Flask框架同时上传多个文件的方法

yipeiwu_com6年前Python基础

本文实例讲述了Python使用Flask框架同时上传多个文件的方法,分享给大家供大家参考。具体如下:

下面的演示代码带有详细的html页面和python代码

import os
# We'll render HTML templates and access data sent by POST
# using the request object from flask. Redirect and url_for
# will be used to redirect the user once the upload is done
# and send_from_directory will help us to send/show on the
# browser the file that the user just uploaded
from flask import Flask, render_template, request, redirect, url_for, send_from_directory
from werkzeug import secure_filename
# Initialize the Flask application
app = Flask(__name__)
# This is the path to the upload directory
app.config['UPLOAD_FOLDER'] = 'uploads/'
# These are the extension that we are accepting to be uploaded
app.config['ALLOWED_EXTENSIONS'] = set(['txt', 'pdf', 'png', 'jpg', 'jpeg', 'gif'])
# For a given file, return whether it's an allowed type or not
def allowed_file(filename):
  return '.' in filename and \
      filename.rsplit('.', 1)[1] in app.config['ALLOWED_EXTENSIONS']
# This route will show a form to perform an AJAX request
# jQuery is loaded to execute the request and update the
# value of the operation
@app.route('/')
def index():
  return render_template('index.html')
# Route that will process the file upload
@app.route('/upload', methods=['POST'])
def upload():
  # Get the name of the uploaded files
  uploaded_files = request.files.getlist("file[]")
  filenames = []
  for file in uploaded_files:
    # Check if the file is one of the allowed types/extensions
    if file and allowed_file(file.filename):
      # Make the filename safe, remove unsupported chars
      filename = secure_filename(file.filename)
      # Move the file form the temporal folder to the upload
      # folder we setup
      file.save(os.path.join(app.config['UPLOAD_FOLDER'],filename))
      # Save the filename into a list, we'll use it later
      filenames.append(filename)
      # Redirect the user to the uploaded_file route, which
      # will basicaly show on the browser the uploaded file
  # Load an html page with a link to each uploaded file
  return render_template('upload.html', filenames=filenames)
 
# This route is expecting a parameter containing the name
# of a file. Then it will locate that file on the upload
# directory and show it on the browser, so if the user uploads
# an image, that image is going to be show after the upload
@app.route('/uploads/<filename>')
def uploaded_file(filename):
  return send_from_directory(app.config['UPLOAD_FOLDER'],
                filename)
if __name__ == '__main__':
  app.run(
    host="0.0.0.0",
    port=int("80"),
    debug=True
  )

index.html代码

<!DOCTYPE html>
<html lang="en">
 <head>
  <link href="bootstrap/3.0.0/css/bootstrap.min.css"
  rel="stylesheet">
 </head>
 <body>
  <div class="container">
   <div class="header">
    <h3 class="text-muted">How To Upload a File.</h3>
   </div>
   <hr/>
   <div>
   <form action="upload" method="post" enctype="multipart/form-data">
   <input type="file" multiple="" name="file[]" class="span3" /><br/>
    <input type="submit" value="Upload" class="span2">
   </form>
   </div>
  </div>
 </body>
</html>

upload.html页面:

<!DOCTYPE html>
<html lang="en">
 <head>
  <link href="bootstrap/3.0.0/css/bootstrap.min.css"
     rel="stylesheet">
 </head>
 <body>
  <div class="container">
   <div class="header">
    <h3 class="text-muted">Uploaded files</h3>
   </div>
   <hr/>
   <div>
   This is a list of the files you just uploaded, click on them to load/download them
   <ul>
    {% for file in filenames %}
     <li><a href="{{url_for('uploaded_file', filename=file)}}">{{file}}</a></li>
    {% endfor %}
   </ul>
   </div>
   <div class="header">
    <h3 class="text-muted">Code to manage a Upload</h3>
   </div>
   <hr/>  
<pre>
@app.route('/upload', methods=['POST'])
def upload():
  # Get the name of the uploaded file
  #file = request.files['file']
  uploaded_files = request.files.getlist("file[]")
  filenames = []
  for file in uploaded_files:
    # Check if the file is one of the allowed types/extensions
    if file and allowed_file(file.filename):
      # Make the filename safe, remove unsupported chars
      filename = secure_filename(file.filename)
      # Move the file form the temporal folder to the upload
      # folder we setup
      file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
      filenames.append(filename)
      # Redirect the user to the uploaded_file route, which
      # will basicaly show on the browser the uploaded file
  # Load an html page with a link to each uploaded file
  return render_template('upload.html', filenames=filenames)
</pre>
   </div>
  </div>
 </body>
</html>

希望本文所述对大家的Python程序设计有所帮助。

相关文章

django2用iframe标签完成网页内嵌播放b站视频功能

django2用iframe标签完成网页内嵌播放b站视频功能

前言: 给自己的网站中加入视频资源,有两种方法,一种是用iframe标签引用外站资源,另一种则使用video标签,获取站内资源进行视频播放。其中前者顾名思义,是将视频资源上传到视频网站...

在Heroku云平台上部署Python的Django框架的教程

Heroku是一个很棒的平台,它有很多的控件,并且搭建环境相对来说也比较容易。本指南中,我将一步一步指导你在Heroku平台上部署一个简单地Django应用 搭建开发环境 Heroku工...

python+pygame简单画板实现代码实例

python+pygame简单画板实现代码实例

疑问:pygame已经过时了吗? 过没过时不知道,反正这玩意官方已经快四年没有更新了。用的人还是蛮多的(相对于其他同类项目),不过大家都是用来写写小东西玩一玩,没有人用这个做商业项目。p...

python的sorted用法详解

列表有自己的sort方法,其对列表进行原址排序,既然是原址排序,那显然元组不可能拥有这种方法,因为元组是不可修改的。 排序,数字、字符串按照ASCII,中文按照unicode从小到大排序...

Python用Bottle轻量级框架进行Web开发

Python用Bottle轻量级框架进行Web开发

当前Python Web开发中的框架算Django最为流行了,但是本文介绍的是一个较为轻量级的Web框架:Bottle框架。理论性的东西就不讲了,直接上实例代码。 1.问题描述 &nbs...