Python实现提取谷歌音乐搜索结果的方法
本文实例讲述了Python实现提取谷歌音乐搜索结果的方法。分享给大家供大家参考。具体如下：
Python的简单脚本，用于提取谷歌音乐搜索页面中的歌曲信息，包括歌曲名，作者，专辑名，现在链接等，最多只提取10页结果。
#! /usr/bin/env python
#coding=utf-8
'''
Created on 2011-8-19
@author: yaoboyuan
'''
from urllib import request,parse
import re,sys
def extractSongRawData(text):
'抓取每一首歌的原始数据'
text = re.sub('\n+','',text)
songList = re.findall('\<tbody.*?\</tbody>',text)
nums = len(songList)
print('search ' + str(nums) + ' songs')
return songList
def translate(text):
'去掉text中的无用字符，转换unicode码'
text = re.sub('\<b>','',text)
text = re.sub('\</b>','',text)
#find the 成 and translate into chinese
s = re.findall('&#([0-9]+);',text)
if len(s)<=0:
return text
else:
text = ''
for i in range(len(s)):
value = int(s[i],10) #from str'123' to 10 base's int 124
text += chr(value) #from value to char
return text
def extractSongName(song):
'提取歌曲名字'
td = re.findall('(?:\<td class\="Title).*(?:\</td>)',song)
name = re.findall('.+?\<a.+?>(.*?)\</a>',td[0])
songName = translate(name[0])
return songName
def extractAuthorName(song):
'提取作者名字'
td = re.findall('(?:\<td class\="Artist).*(?:\</td>)',song)
name = re.findall('.+?\<a.+?>(.*?)\</a>',td[0])
authorName = name[0]
authorName = translate(authorName)
return authorName
def extrackAlbumName(song):
'提取专辑名字'
td = re.findall('(?:\<td class\="Album).*(?:\</td>)',song)
name = re.findall('.+?\<a.+?>(.*?)\</a>',td[0])
albumName = translate(name[0])
return albumName
def extractID(song):
'提取歌曲id'
td = re.findall('''\<tbody id\="([a-zA-Z0-9]+)"''',song)
if len(td)>0:
return td[0]
else:
return song
def extractLink(song):
'提取歌曲下载链接'
td = re.findall('''\<td class\="Icon.*?(?=title\="下载").*?onclick\="(.*?)>''',song)
if len(td) == 0:
return 'NULL'
s = str(td[0])
rawLink = re.findall('http.*?(?=\?)',s)
if len(rawLink) == 0:
return s
link = rawLink[0]
link = re.sub('%3D','=',link)
id = extractID(song)
return link + '?id=' + id
def extractPageNums(text):
'提取返回结果的页数，最多要10页'
pageList = re.findall('page_link',text)
return len(pageList)
def extractSongInfo(song):
'提取歌曲信息，返回歌曲列表'
songList = []
for i in range(len(song)):
songName = extractSongName(song[i])
authorName = extractAuthorName(song[i])
albumName = extrackAlbumName(song[i])
link = extractLink(song[i])
songItem = [songName,authorName,albumName,link]
songList.append(songItem)
index = ''
if i<9:
index = '0' + str(i+1)
else:
index = str(i + 1)
#print(index + ' ' + songName + ' ' + authorName + ' ' + albumName + ' ' + link)
return songList
def main():
while True:
url = 'http://www.google.cn/music/search?q='
key = input('请输入歌曲名字或关键字:')
key = parse.quote(key) #统一编码成utf-8
url += key
mf = request.urlopen(url)
c = mf.readall()
c = str(c,encoding = 'utf-8')
num = extractPageNums(c)
print(str(num+1) + ' pages found')
song = extractSongRawData(c)
songList = extractSongInfo(song)
#if the result great than 2 pages, then request all pages
if num>0:
for i in range(num):
start = (i+1)*20
next_page = '&cat=song&start=%d'%(start)
#next_page = parse.quote(next_page) #统一编码成utf-8
url += next_page
mf = request.urlopen(url)
c = mf.readall()
c = str(c,encoding = 'utf-8')
song = extractSongRawData(c)
songList += extractSongInfo(song) #find all results
for i in range(len(songList)): #print the result
index = ''
if i<9:
index = '0' + str(i+1)
else:
index = str(i + 1)
print(index + ' ' + str(songList[i]))
if __name__ == '__main__':
main()
希望本文所述对大家的Python程序设计有所帮助。
