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用python实现对比两张图片的不同

yipeiwu_com7年前 (2020-03-06)Python基础

from PIL import Image
from PIL import ImageChops 
def compare_images(path_one, path_two, diff_save_location):
  """
  比较图片，如果有不同则生成展示不同的图片
  @参数一: path_one: 第一张图片的路径
  @参数二: path_two: 第二张图片的路径
  @参数三: diff_save_location: 不同图的保存路径
  """
  image_one = Image.open(path_one)
  image_two = Image.open(path_two)
  try: 
    diff = ImageChops.difference(image_one, image_two)
    if diff.getbbox() is None:
    # 图片间没有任何不同则直接退出
      print("【+】We are the same!")
    else:
      diff.save(diff_save_location)
  except ValueError as e:
    text = ("表示图片大小和box对应的宽度不一致，参考API说明：Pastes another image into this image."
        "The box argument is either a 2-tuple giving the upper left corner, a 4-tuple defining the left, upper, "
        "right, and lower pixel coordinate, or None (same as (0, 0)). If a 4-tuple is given, the size of the pasted "
        "image must match the size of the region.使用2纬的box避免上述问题")
    print("【{0}】{1}".format(e,text))
if __name__ == '__main__':
  compare_images('1.png',
          '2.png',
          '我们不一样.png')

执行结果：

第二种方法：

from PIL import Image
import math
import operator
from functools import reduce
def image_contrast(img1, img2):
  image1 = Image.open(img1)
  image2 = Image.open(img2)
  h1 = image1.histogram()
  h2 = image2.histogram()
  result = math.sqrt(reduce(operator.add, list(map(lambda a,b: (a-b)**2, h1, h2)))/len(h1) )
  return result
if __name__ == '__main__':
  img1 = "./1.png" # 指定图片路径
  img2 = "./2.png"
  result = image_contrast(img1,img2)
  print(result)

如果两张图片完全相等，则返回结果为浮点类型“0.0”，如果不相同则返回结果值越大。

同样用上面两张图片，执行结果为38，还是比较小的：