PHP+MySql+jQuery实现的"顶"和"踩"投票功能
本文实例为大家分享了基于PHP+jQuery+MySql实现红蓝(顶踩)投票代码，供大家参考，具体内容如下
数据库操作：
CREATE TABLE IF NOT EXISTS `votes` ( `id` int(10) NOT NULL AUTO_INCREMENT, `likes` int(10) NOT NULL DEFAULT '0', `unlikes` int(10) NOT NULL DEFAULT '0', PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; INSERT INTO `votes` (`id`, `likes`, `unlikes`) VALUES (1, 30, 10); CREATE TABLE IF NOT EXISTS `votes_ip` ( `id` int(10) NOT NULL, `vid` int(10) NOT NULL, `ip` varchar(40) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=utf8;
div：
<div class="digg"> <div id="dig_up" class="digup"> <span id="num_up"></span> <p>很好，很强大！</p> <div id="bar_up" class="bar"><span></span><i></i></div> </div> <div id="dig_down" class="digdown"> <span id="num_down"></span> <p>太差劲了！</p> <div id="bar_down" class="bar"><span></span><i></i></div> </div> <div id="msg"></div> </div>
css：
.digg{width:420px; height:120px; margin:80px auto 20px auto; position:relative}
#dig_up,#dig_down{width:200px; height:48px; margin:10px; position:relative;
border:1px solid #d3d3d3; padding-left:42px; cursor:pointer}
.digup{background:url(diggs.png) no-repeat 4px 2px;}
.digup_on{background:url(diggs.png) no-repeat 4px -49px;}
.digdown{background:url(diggs.png) no-repeat 4px -102px;}
.digdown_on{background:url(diggs.png) no-repeat 4px -154px;}
#num_up,#num_down{position:absolute; right:6px; top:18px; font-size:20px;}
#dig_up p{height:24px; line-height:24px; color:#360}
#dig_down p{height:24px; line-height:24px; color:#f30}
.bar{width:100px; height:12px; line-height:12px; border:1px solid #f0f0f0;
position:relative; text-align:center}
.bar span{display:block; height:12px; }
.bar i{position:absolute; top:0; left:104px;}
#bar_up span{background:#360}
#bar_down span{background:#f60}
#msg{position:absolute; right:20px; top:40px; font-size:18px; color:#f00}
jquery：
$(function(){
//鼠标滑向和离开投票按钮时，变换背景样式
$("#dig_up").hover(function(){
$(this).addClass("digup_on");
},function(){
$(this).removeClass("digup_on");
});
$("#dig_down").hover(function(){
$(this).addClass("digdown_on");
},function(){
$(this).removeClass("digdown_on");
});
//初始化数据
getdata("do.php",1);
//单击“顶”时
$("#dig_up").click(function(){
getdata("do.php?action=like",1);
});
//单击“踩”时
$("#dig_down").click(function(){
getdata("do.php?action=unlike",1);
});
});
---------------------------------------
function getdata(url,sid){
$.getJSON(url,{id:sid},function(data){
if(data.success==1){//投票成功
$("#num_up").html(data.like);
//通过控制宽度来显示百分比进度条效果
$("#bar_up span").css("width",data.like_percent);
$("#bar_up i").html(data.like_percent);
$("#num_down").html(data.unlike);
$("#bar_down span").css("width",data.unlike_percent);
$("#bar_down i").html(data.unlike_percent);
}else{//投票失败
$("#msg").html(data.msg).show().css({'opacity':1,'top':'40px'})
.animate({top:'-50px',opacity:0}, "slow");
}
});
}
php：
include_once("connect.php");//连接数据库
$action = $_GET['action'];
$id = 1;
$ip = get_client_ip();//获取ip
if($action=='like'){//顶
likes(1,$id,$ip);
}elseif($action=='unlike'){//踩
likes(0,$id,$ip);
}else{
echo jsons($id);
}
------------------------------------
function likes($type,$id,$ip){
$ip_sql=mysql_query("select ip from votes_ip where vid='$id' and ip='$ip'");
$count=mysql_num_rows($ip_sql);
if($count==0){//还没有顶过
if($type==1){//顶
$sql = "update votes set likes=likes+1 where id=".$id;
}else{//踩
$sql = "update votes set unlikes=unlikes+1 where id=".$id;
}
mysql_query($sql);
$sql_in = "insert into votes_ip (vid,ip) values ('$id','$ip')";
mysql_query($sql_in);
if(mysql_insert_id()>0){
echo jsons($id);
}else{
$arr['success'] = 0;
$arr['msg'] = '操作失败，请重试';
echo json_encode($arr);
}
}else{
$msg = $type==1?'您已经顶过了':'您已经踩过了';
$arr['success'] = 0;
$arr['msg'] = $msg;
echo json_encode($arr);
}
}
-----------php-------------------------
function jsons($id){
$query = mysql_query("select * from votes where id=".$id);
$row = mysql_fetch_array($query);
$like = $row['likes'];
$unlike = $row['unlikes'];
$arr['success']=1;
$arr['like'] = $like;
$arr['unlike'] = $unlike;
$like_percent = round($like/($like+$unlike),3)*100;
$arr['like_percent'] = $like_percent.'%';
$arr['unlike_percent'] = (100-$like_percent).'%';
return json_encode($arr);
}
以上就是本文的全部内容，希望对大家学习php程序设计有所帮助。