Python制作Windows系统服务
最近有个Python程序需要安装并作为Windows系统服务来运行，过程中碰到一些坑，整理了一下。
Python服务类
首先Python程序需要调用一些Windows系统API才能作为系统服务，具体内容如下：
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import sys
import time
import win32api
import win32event
import win32service
import win32serviceutil
import servicemanager
class MyService(win32serviceutil.ServiceFramework):
_svc_name_ = "MyService"
_svc_display_name_ = "My Service"
_svc_description_ = "My Service"
def __init__(self, args):
self.log('init')
win32serviceutil.ServiceFramework.__init__(self, args)
self.stop_event = win32event.CreateEvent(None, 0, 0, None)
def SvcDoRun(self):
self.ReportServiceStatus(win32service.SERVICE_START_PENDING)
try:
self.ReportServiceStatus(win32service.SERVICE_RUNNING)
self.log('start')
self.start()
self.log('wait')
win32event.WaitForSingleObject(self.stop_event, win32event.INFINITE)
self.log('done')
except BaseException as e:
self.log('Exception : %s' % e)
self.SvcStop()
def SvcStop(self):
self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
self.log('stopping')
self.stop()
self.log('stopped')
win32event.SetEvent(self.stop_event)
self.ReportServiceStatus(win32service.SERVICE_STOPPED)
def start(self):
time.sleep(10000)
def stop(self):
pass
def log(self, msg):
servicemanager.LogInfoMsg(str(msg))
def sleep(self, minute):
win32api.Sleep((minute*1000), True)
if __name__ == "__main__":
if len(sys.argv) == 1:
servicemanager.Initialize()
servicemanager.PrepareToHostSingle(MyService)
servicemanager.StartServiceCtrlDispatcher()
else:
win32serviceutil.HandleCommandLine(MyService)
pyinstaller打包
pyinstaller -F MyService.py
测试
# 安装服务 dist\MyService.exe install # 启动服务 sc start MyService # 停止服务 sc stop MyService # 删除服务 sc delete MyService
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持【听图阁-专注于Python设计】。