Python 解码Base64 得到码流格式文本实例
我就废话不多说了，直接上代码吧！
# coding:utf8
import base64
def BaseToFlow():
while True:
str = input("Please input src: ")
flag = input("Please input Decode - 1 or Encode - 2: ")
if str == "":
str = "ApIAGBcEAAAEBO6x3nLykEEhjWMX1wHs"
if flag == "":
flag = "1"
if flag == "1":
print("Decoding ...")
dst = base64.b64decode(str)
# print(type(dst))
# <class 'bytes'>
# print(dst)
# b'\x02\x92\x00\x18\x17\x04\x00\x00\x04\x04\xee\xb1\xder\xf2\x90A!\x8dc\x17\xd7\x01\xec'
# print(dst.hex()) --去掉\0x前缀 得到一个字符串
# 02920018170400000404eeb1de72f29041218d6317d701ec
HexFormat(dst.hex())
elif flag == "2":
print("Encoding ...")
dst = base64.b64encode(str)
print(dst)
def HexFormat(str):
"""
:param str: 16进制连续字符串
:return: 码流格式的16进制串
"""
i = 1
str2 = ""
while (i <= len(str)):
str2 = str2 + str[i - 1] + str[i] + " "
if (i + 1) %16 == 0 and (i + 1) % 32 != 0:
str2 = str2 + " "
elif (i + 1) %32 == 0:
str2 = str2 + "\n"
i = i + 2
if __name__ == '__main__':
BaseToFlow()
结果：
Please input src: Please input Decode - 1 or Encode - 2: Decoding ... 02 92 00 18 17 04 00 00 04 04 ee b1 de 72 f2 90 41 21 8d 63 17 d7 01 ec
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